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Frequently Asked Questions About Peltier Elements (FAQ)

Fundamentals & physics

What is the difference between the Peltier, Seebeck and Thomson effects?

These are the three basic thermoelectric effects. The Seebeck effect describes the generation of an electrical voltage when two junctions of dissimilar materials are held at different temperatures – it is the basis of thermocouples and thermoelectric generators. The Peltier effect is its reverse: an applied current transports heat from one junction to the other – it is the basis of Peltier elements. The Thomson effect describes the additional reversible absorption or release of heat along a single current-carrying conductor in which a temperature gradient exists; it is of minor importance in practical sizing.

Which semiconductor material are Peltier elements made of?

Almost all common cooling modules are made of doped bismuth telluride (Bi₂Te₃), because around room temperature this material offers the best compromise between electrical conductivity and low thermal conductivity. Other material systems are used for other temperature ranges:

MaterialOptimum operating rangeTypical use
Bismuth antimony (BiSb) below room temperature low-temperature special applications
Bismuth telluride (Bi₂Te₃) approx. −50 °C to +150 °C standard for cooling modules
Lead telluride (PbTe) approx. 250 °C to 450 °C mainly power generation
Silicon-germanium (SiGe) approx. 500 °C to 1,000 °C radioisotope batteries, space

Bi₂Te₃ is processed at around 150 °C or 230 °C (high-temperature variant). The maximum operating temperature is about 30 K below the respective processing temperature.

What is a thermocouple – and why does the number of couples determine the electrical characteristics?

A thermocouple (couple) consists of one p-doped and one n-doped semiconductor leg, connected electrically in series and thermally in parallel. A Peltier element typically contains from 7 to more than 250 such couples. Since all couples are electrically in series, their voltage drops add up: each couple drops around 0.12 V. A module with 127 couples therefore has a maximum voltage of about 15.2 V. The same cooling power can thus be realised either with many couples at high voltage and low current, or with few couples at low voltage and high current.

What does the figure of merit Z or ZT mean?

The figure of merit summarises the three relevant material properties:

Z = S² · σ / λ      ZT = Z · T

with S = Seebeck coefficient, σ = electrical conductivity, λ = thermal conductivity and T = absolute temperature. Good Bi₂Te₃ modules reach ZT values around 0.8 to 1.0. The figure of merit directly determines the achievable ΔTmax – which is why high-quality and basic modules of the same form factor differ markedly in performance.

What is the COP and why does it matter more than cooling power alone?

The COP (coefficient of performance) is the ratio of pumped heat to electrical power input:

COP = Qc / Pel

It determines the power-supply size, energy cost and, above all, the amount of heat the heat sink must dissipate – because the hot side must always release Qh = Qc + Pel. At small ΔT the COP can be well above 1; at large ΔT it drops to around 0.1 and below. The COP maximum is usually reached below 50 % of the maximum current.

Reading key figures & datasheets correctly

What do Qmax, ΔTmax, Imax and Umax mean?

ValueDefinitionValid at
Qmax (Qc max) Maximum heat-pumping power of the cold side ΔT = 0 K, Imax, Umax
ΔTmax Maximum temperature difference between cold and hot side Qc = 0 W, Imax, Umax
Imax Current at which ΔTmax is reached —
Umax Corresponding voltage at Imax and ΔTmax —

All figures apply for a defined hot-side temperature – usually Th = 300 K (27 °C), in some datasheets 50 °C. Comparing two modules is only valid at the same reference temperature.

Why can I never reach ΔTmax and Qmax at the same time?

Both values are limits in two opposite operating points. Qmax applies at ΔT = 0 K, i.e. when the cold and hot sides are equally warm – then no temperature difference is produced. ΔTmax applies at Qc = 0 W, i.e. without any useful load. Every real operating point lies in between: the more heat the module has to pump, the smaller the achievable temperature difference. The characteristic Qc = f(ΔT) runs approximately linearly between the two limits.

How does ΔTmax change with the hot-side temperature?

ΔTmax rises with increasing hot-side temperature, because the Seebeck coefficient and material quality are temperature-dependent in the relevant range. A standard module that reaches about 70 K at Th = 27 °C achieves about 75 K at Th = 50 °C and around 83 K at Th = 80 °C. However, this does not mean the cold side becomes colder – the absolute cold-side temperature still rises. For low target temperatures, the coldest possible hot side remains decisive.

Why does a module deliver a higher ΔT in vacuum than in air?

The datasheet values for ΔTmax are measured in vacuum. In air, three parasitic heat paths act back from the hot to the cold side: heat conduction through the gas between the legs, free convection at the cold side, and condensation of humidity. In practice the achievable ΔT in air is therefore typically 3 to 8 K below the datasheet value, relatively more for small modules. Anyone who needs the full ΔT works in an evacuated or dry protective-gas enclosure.

What is the difference between a "suitable" and an "optimal" module?

Suitable is any module that delivers the required cooling power at the required temperature difference at all – there are usually several. Optimal is the one that solves the task with the best COP, i.e. the lowest electrical power and therefore the smallest heat sink and power supply. The optimal module is almost always slightly larger than the just-suitable one and is operated well below Imax. We check this point as standard during consulting.

At which operating point should I run a Peltier element?

Common and sensible is 50 to 75 % of Imax/Umax. The reason: cooling power approaches its maximum exponentially – the last 30 % or so is bought with disproportionately high electrical power, which has to be dissipated as additional Joule heat via the heat sink. Whoever wants maximum efficiency goes below 50 % Imax; whoever needs maximum heat-pumping power in a tight space goes higher – at the cost of efficiency and service life.

Sizing & calculation

What information do I need before I can select a Peltier element?

For a reliable design we need nine inputs:

  1. Required temperature of the object to be cooled (Tc)
  2. Heat to be removed (active power dissipation, Qc)
  3. Required cool-down or response time
  4. Ambient temperature and its variation
  5. Parasitic heat loads through conduction, convection and radiation
  6. Available space for the module and the heat sink
  7. Available electrical power (voltage, current)
  8. Required control accuracy
  9. Type of heat dissipation and expected hot-side temperature (Th)
Rule of thumb from practice: in about half of all enquiries the design fails not on the module but on points 6 and 9 – the heat sink is too small for the sum of useful load and electrical power.

How exactly do I go about selecting a module?

Sizing is an iterative procedure, because the hot-side temperature depends on the electrical power – and the electrical power in turn depends on the temperature difference. Procedure in six steps:

  1. Estimate the hot-side temperature: Th = Tamb + (Qc + Pel) · Rth,heat sink
  2. Form the temperature difference: ΔT = Th − Tc
  3. Read the required current at this ΔT from the Qc characteristic field
  4. Read the corresponding voltage from the U-I field → actual Pel = U · I
  5. Recalculate Th with the actual Pel
  6. Repeat steps 2–5 until Th changes by less than 0.1 K

Worked example

Given: useful load Qc = 20 W, target temperature Tc = 5 °C, ambient Tamb = 25 °C, fan heat sink with Rth = 0.35 K/W.

IterationAssumed PelQh = Qc+PelThΔT
1 20 W (start value) 40 W 39.0 °C 34.0 K
2 32 W (read off) 52 W 43.2 °C 38.2 K
3 36 W (read off) 56 W 44.6 °C 39.6 K
4 37.5 W (read off) 57.5 W 45.1 °C 40.1 K

The procedure converges after four passes: the module must pump 20 W at ΔT ≈ 40 K and needs around 37.5 W electrically for this – so the heat sink must dissipate almost 58 W, not 20 W. The COP is 0.53.

The Pel values come from the characteristic field of the respective module and are examples here. We are happy to run the actual calculation for your application – get in touch.

How do I size the heat sink?

The decisive quantity is the permissible thermal resistance:

Rth,req = (Th,perm − Tamb) / Qh   with   Qh = Qc + Pel

From the example above: if Th must not exceed 45 °C, then at 25 °C ambient and 57.5 W of waste heat, Rth ≤ 0.35 K/W results. For orientation:

Heat-sink typeTypical RthNote
Passive, free convection 1.5 – 5 K/W only for small loads < 10 W
Active, axial fan 0.15 – 0.8 K/W standard solution
Liquid-cooled 0.02 – 0.1 K/W highest power density, higher cost

Blowing onto the front of the heat-sink base is most effective, because the highest heat-flux density is present there. Suitable air and liquid heat sinks as well as complete Peltier assemblies can be found under Temperature management.

Which passive heat loads do I have to add?

Besides the active useful load, three parasitic heat inputs act on the cold side. On small modules they often dominate the design:

1. Conduction through connecting wires and mounts

Q = λ · A · ΔT / L

Example: two copper strands 0.5 mm² (AWG 20), 50 mm free, λCu = 400 W/(m·K), ΔT = 40 K → 0.32 W. On a miniature module with Qmax = 1 W that is already 30 % of the power. Remedy: thinner strands, manganin or constantan wire, longer free length, thermal anchoring of the wires to an intermediate stage.

2. Convection at the cold side

Q = α · A · ΔT   (α ≈ 5–10 W/(m²·K) for free convection)

Example: 10 cm² cold surface, ΔT = 40 K → 0.2 to 0.4 W.

3. Thermal radiation

Q = ε · σ · A · (Th⁴ − Tc⁴)

Example: 10 cm², ε = 0.9, Th = 25 °C, Tc = −15 °C → around 0.18 W. Remedy: bare, polished metal surfaces (low ε) and radiation shields.

How do I calculate the cool-down time?

The mass to be cooled requires transient power in addition to the steady-state load:

Qtransient = m · cp · ΔT / t

Example: 100 g of aluminium (cp = 900 J/(kg·K)) is to be cooled by 20 K in 60 s → 30 W extra. If a phase change is passed through (e.g. water/ice), the latent heat is added. Short cool-down times are almost always the most expensive part of a specification – check whether the time requirement is really necessary.

Can I combine several Peltier elements?

Yes. For larger areas or higher loads, several modules are connected thermally in parallel (side by side between heat sink and cold plate) and electrically in series. This way all modules carry the same current and work at the same operating point. Requirements:

  • Modules from the same production batch with tight height tolerance (±0.03 mm)
  • Uniform mounting pressure across all modules – ideally via a common, stiff pressure plate
  • Sufficient spacing between the modules so the cold plate is not distorted

An electrical parallel connection is to be avoided: the smallest resistance differences lead to unequal current sharing.

When do I need a cascade (multi-stage module)?

As soon as the required temperature difference lies above what is sensibly achievable single-stage – i.e. from about 65 to 70 K under load. In a cascade, a smaller upper stage sits on a larger lower stage, which must dissipate all of the upper stage's waste heat. Typical guide values:

DesignΔTmax (vacuum, Th = 27 °C)Characteristic
Single-stage approx. 66 – 83 K best price/performance ratio
Two-stage approx. 91 – 106 K much lower Qc, higher price
Three-stage approx. 111 K special applications, very small loads

Rule of thumb: each additional stage adds about 20 to 25 K, but costs roughly a factor of 3 to 5 in heat-pumping power. Our cascade types can be found in the catalogue.

Construction, form factor & manufacturing

Al₂O₃ or AlN – which ceramic is the right one?

PropertyAl₂O₃ (aluminium oxide)AlN (aluminium nitride)
Thermal conductivity approx. 24 – 30 W/(m·K) approx. 150 – 180 W/(m·K)
Cost standard considerably higher
Typical use standard and power modules miniature modules, high heat-flux density

On large modules with moderate heat-flux density the difference is small, because the ceramic's share of the total resistance stays small. On miniature modules with high power density, AlN can bring several kelvin of usable ΔT – there the surcharge is worthwhile.

What influence does the geometry of the semiconductor legs have?

The decisive factor is the aspect ratio of leg height to cross-sectional area. Short, thick legs give low electrical resistance and high currents at low voltage – but also higher heat back-flow. Long, thin legs give higher voltage at low current and a better ΔT, but are mechanically more sensitive and build taller. For the same base area, roughly: low height = more Qc per area, greater height = better ΔT and better COP.

What height tolerance do Peltier elements have?

Standard modules are usually manufactured to ±0.3 mm. For applications in which several modules are clamped together between heat sink and cold plate, or in which a defined clamping force is required, lapped versions with ±0.03 mm are available. Please state the required tolerance with your enquiry – it is price-relevant.

Which internal solders are used and what is the maximum process temperature?

The legs are soldered to the copper bridges. The solder used limits the permissible temperature of the entire module:

SolderMelting pointMax. short-term operating/process temperature
BiSn 139 °C approx. 110 – 120 °C
SnPb / SnAg 183 °C approx. 155 – 165 °C
High-temperature solder 232 °C approx. 200 – 210 °C

The permissible temperature is 20 to 30 K below the melting point in each case. Regardless of this: in continuous operation above 120 °C, copper diffuses into the semiconductor material and the module permanently loses performance. If a module is soldered into an assembly, the process profile (reflow, hand soldering) must match the internal solder – please coordinate in advance.

How small can Peltier elements be?

Miniature and micro modules are available from a few square millimetres of base area and heights below 1 mm, some with only 7 thermocouples. They are typically integrated into TO packages (TO-8, TO-56, butterfly) to stabilise laser diodes, IR detectors or sensors. Note: at these sizes the parasitic heat loads dominate (see above) and the mechanical load capacity is limited. See miniature types.

What are thin-film Peltier elements and when do they make sense?

In thin-film modules the thermoelectric material is deposited as a layer instead of being sawn from blocks ("bulk"). Advantages are a very low height and extremely short response times in the millisecond range, which makes them interesting for fast-switched applications. Disadvantages: low absolute heat-pumping power, usually smaller ΔT and considerably higher cost. For the vast majority of cooling tasks, bulk technology is the more economical choice.

What are Peltier elements with a centre hole for?

The central hole allows a beam path, a sensor, a shaft or a screw connection to be led through the middle of the module. Typical applications are optical assemblies, detector cooling and cold plates that must be bolted in the centre. Note: the hole reduces the active area and thus Qc; in addition, the bolt must not introduce shear forces. See types with a hole.

Can a temperature sensor be integrated directly on the module?

Yes. NTC thermistors can be applied directly to the cold-side ceramic and wired in. This considerably shortens the control path, because the sensor sits right at the controlled surface instead of somewhere in the assembly. For precise measurements, four-wire (Kelvin) measurement is recommended, since with thin connecting wires the lead resistance would otherwise enter the result. Sensor integration is also possible on multi-stage modules. Such versions run as special types – please enquire.

Mounting & mechanics

What is the right mounting pressure – and where is the limit?

Recommended is 3 to 8 kg/cm² (around 30 to 80 N/cm²). In this range the thermal contact resistance is already clearly reduced without mechanically overstressing the module. The design upper limit is 15 kg/cm² (about 200 psi); good modules only fail mechanically well above this, but beyond this value additional pressure brings nothing thermally and only increases the risk of breakage. What matters is not so much the absolute value as the uniform distribution: spring-loaded screws with a stiff pressure plate are preferable to rigid bolting.

May I bond or solder a Peltier element?

In principle yes, but with restrictions:

  • Clamping is the standard solution and the most robust variant for temperature cycling as well as shock and vibration.
  • Bonding with a thermally conductive adhesive makes sense when bolting is not possible by design. With epoxy adhesives, observe the curing temperature – it must not endanger the internal solder.
  • Soldering is only possible on modules metallised on both sides and is practically limited to small form factors up to about 12 × 12 mm.

With a rigid connection on both sides (bonding or soldering) combined with large temperature swings, considerable shear stresses arise – then clamping is preferable.

What is CTE mismatch and how do I avoid it?

The cold and hot sides of a Peltier element work at very different temperatures. If the adjacent parts have a different coefficient of thermal expansion (CTE) than the ceramic, shear stresses arise – especially at the corners of the module, where the distance to the centre is greatest. Countermeasures:

  • Choose materials with a similar CTE (Al₂O₃ ≈ 7 · 10⁻⁶ /K; copper ≈ 17, aluminium ≈ 23 · 10⁻⁶ /K)
  • Rigid connection on only one side, clamp the other side or provide it with a compliant interface
  • Leave the corner areas of the bonding or soldering surface free so the corners can move freely
  • Use the smallest possible modules – the offset grows linearly with the edge length

Does the module height change during operation?

Yes, slightly. In operation the hot side expands while the cold side shrinks – the overall height thus typically changes in the range of a few micrometres to a few hundredths of a millimetre, depending on height and ΔT. For pre-loaded assemblies with tight tolerances, optical alignments and spring-loaded clamping, this effect must be taken into account.

Which forces may a Peltier element absorb?

Compressive forces perpendicular to the surface are uncritical as long as they are introduced uniformly (see above). Shear forces parallel to the surface, on the other hand, are critical and must be kept away by design – they load the solder joints of the legs directly. The connecting leads must also not carry any tensile force: they are soldered to the ceramic and come loose under tension or repeated bending. Therefore provide strain relief for the leads in the immediate vicinity of the module.

Which side gets warm?

With correct connection of the supply voltage, the side to which the wires are soldered always gets warm. This side belongs on the heat sink. By reversing the polarity, the cold and hot sides swap – this is permissible for heating operation, but the assembly must then be thermally designed for both cases.

Power supply & control

What requirements does a Peltier element place on the power supply?

Peltier elements are a resistive DC load with a positive resistance temperature coefficient of around 0.5 % per K. The decisive factor is the ripple of the supply:

ApplicationRecommended ripple
General, maximum permissible ≤ 10 %
Recommended target value < 5 %
Cascades / max. ΔT, sensitive measurement < 2 %

Background: the AC component produces Joule heat but contributes nothing to heat transport – the achievable ΔT drops. In measurement setups there is the added issue that AC components on the module leads can disturb the measurement signals, even though the Peltier element itself is electrically very quiet.

Can I drive Peltier elements by PWM?

Yes, PWM is common and cost-effective, but it costs performance: the pulsed current produces more Joule heat than a direct current of the same average power, so ΔT and COP fall measurably. Recommendations:

  • Choose a sufficiently high switching frequency (usually > 1 kHz) so the module integrates thermally
  • Provide an output filter (LC) – this brings the behaviour close to that of a linear supply
  • For the highest demands on ΔT and stability: a linear, current-controlled output stage

Suitable controllers can be found under Peltier temperature controllers.

Which type of control is the right one?

MethodAchievable accuracyAssessment
Two-point (ON/OFF) approx. ±1 K simple, but stresses the module heavily – not recommended
Proportional (fixed power) depends on load stability suitable for constant load and environment
Closed loop (PID) ±0.1 K and better standard for precise applications

Why is two-point control harmful for Peltier elements?

Every ON/OFF cycle is a complete thermal cycle for the module: the legs and solder joints expand and contract again. Thermal cycles are by far the dominant wear mechanism of Peltier elements – in steady-state operation the MTBF is over 200,000 hours, whereas in hard cycling operation it is a few tens of thousands of cycles. Analogue control or a short, high-frequency pulsing is therefore considerably gentler mechanically and extends the service life significantly.

Environment, protection & service life

How do I protect the module against condensation?

As soon as the cold side falls below the dew point of the ambient air, moisture condenses. This leads to corrosion of the inner copper bridges, to leakage currents and, in the extreme, to a short circuit. For orientation: at 25 °C and 50 % relative humidity the dew point is around 14 °C, at 70 % r.h. already about 19 °C. Measures, in order of effectiveness:

  1. Encapsulate the cold area and use dry protective gas or evacuate it
  2. Seal the module peripherally (silicone or epoxy) and additionally seal the edge zone with closed-cell foam tape
  3. Provide a designed condensate drain where condensation is unavoidable

A seal costs around 3 to 4 % of performance through heat feedback via the sealing material and should therefore be used only where it is needed.

Silicone or epoxy – which sealing when?

 Silicone (suffix S)Epoxy (suffix E)
Flexibility high, follows temperature swings brittle
Temperature cycling well suited not recommended
Max. operating temperature high ≤ 80 °C
Outgassing slightly possible none
Water absorption higher low
Recommended for standard case, cyclic operation optics, sensors, outgassing-critical setups

Are Peltier elements vacuum-compatible?

In vacuum, Peltier elements actually work better, because convection and gas heat conduction as parasitic paths are eliminated. However, outgassing must be considered: for high and ultra-high vacuum, choose unsealed modules, since silicone and in part also epoxy seals outgas. Likewise, thermal greases must be replaced by dry interfaces (graphite foil, indium foil, direct metal connection). Please coordinate UHV applications with us – material selection is decisive here.

What is the service life in steady-state operation?

In constant operation without significant temperature swings, the MTBF is over 200,000 hours – equivalent to more than 20 years of continuous operation. Peltier elements have no moving parts, no refrigerant and no wear in the classical sense. The service life is limited almost exclusively by thermal cycles, overheating and moisture ingress.

How many temperature cycles does a Peltier element withstand?

This depends on four factors: number of cycles, magnitude of the temperature swing, absolute upper limit and rate of change. Typical test results for high-quality modules:

LoadCycles reached
30 °C ↔ 100 °C, cycle time 5 min MTBF approx. 68,000 cycles
5 °C ↔ 95 °C > 100,000 cycles possible
ON/OFF switching, 7.5 s on / 7.5 s off approx. 125,000 h ≙ around 30 million cycles

Important: modules of a higher temperature class (e.g. 200 °C) are considerably more cycle-resistant even at cycles well below their limit temperature. Smaller modules (edge length ≤ 30 mm) behave better under thermal cycling than large ones. For pronounced cyclic operation we recommend our cycler modules.

How strongly does a module age at permanently high temperature?

Considerably less than is often assumed. Under continuous loading at 150 °C, the following degradation was measured over 42 months: around 2.5 % loss of ΔTmax in the first 12 months, then a further 1.3 % over 30 months, with the material parameters stabilising. Ageing is therefore degressive, not linear. It only becomes critical above 120 °C continuous operation, through copper diffusion, and near the melting point of the internal solder.

How does the ambient temperature affect service life?

A high ambient temperature raises the hot-side temperature and thus the mean operating temperature of all solder joints – the ageing processes accelerate. At the same time the module has to work harder for the same ΔT, which increases the Joule heat and the current. A well-sized heat sink is therefore not only a performance question but, above all, a service-life question.

Part-number system of the uwe Peltier elements (UEPT)

How is the type designation structured?

UEPT – [Series] – [Couples] – [Imax×10][Configuration code][Base code][Sealing] [-Custom cable] [-Add-on]
FieldMeaningExample
UEPT Prefix for a uwe electronic Peltier element (thermoelectric module / TEC) UEPT
Series First digit = number of stages; 2nd and 3rd digit = internal series/size code 140
Couples Number of p/n thermocouples (3-digit) 127 = 127 couples
Imax × 10 Maximum current (3-digit) 085 = 8.5 A
Letter Internal configuration code C
Base code Standard configuration code 200
Sealing Suffix, where specified S = silicone
-NNN Custom cable length in mm -450
-PCM PCM printing -PCM

How do I identify the number of stages?

From the first digit of the series:

SeriesStagesDesignTypical ΔTmax
1xx single-stage standard/high-performance, square and rectangular 66 – 83 K
1RE single-stage rectangular/stock series 66 – 83 K
2xx two-stage cascade 91 – 106 K
3xx three-stage cascade approx. 111 K
4xx single-stage with centre hole 66 – 83 K
5xx single-stage cycler modules 66 – 83 K

Can I derive the module size from the type designation?

Approximately, yes. On uwe standard modules, one thermocouple occupies roughly 12.8 mm² of base area. This gives:

Area ≈ number of couples × 12.8 mm²

Examples: 63 couples ≈ 806 mm² ≈ 40 × 20 mm; 127 couples ≈ 1,626 mm² ≈ 40 × 40 mm. Please take the actual edge length from the datasheet – the packing density differs in particular for miniature, cascade and centre-hole types.

What does the letter after the maximum current mean?

The letter is an internal configuration code from uwe electronic. It has no bearing on the module specification – two modules with identical remaining fields are functionally equivalent.

Which sealing suffixes are there?

SuffixMeaning
(no suffix) no sealing
S silicone
E epoxy
P parylene
M metallised, both sides – for direct soldering
G graphite foil

Note: the sealing is not encoded in every type designation. In case of doubt, the datasheet or our stock and order list is authoritative.

Which cable lengths are standard?

Depending on the series, standard is 120 mm or 133 mm. Deviating lengths are appended as a three-digit millimetre value, for example -450 for 450 mm or -150 for 150 mm.

Example: what does UEPT-140-127-085C200S tell me?

FieldValueMeaning
UEPT — uwe electronic Peltier element
Series 140 single-stage (first digit 1), internal size code 40
Couples 127 127 p/n couples → approx. 1,626 mm², equals 40 × 40 mm
Imax 085 8.5 A
Configuration code C internal marking, no relevance to the specification
Base code 200 standard configuration code
Sealing S silicone

From 127 couples × approx. 0.12 V, a maximum voltage of around 15.2 V also follows.

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